How many moles of KMnO4 are reduced?

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How many moles of KMnO4 are reduced by Ki?

The oxidation number of Manganese (Mn) will decrease from +7 in \$KMn{O_4}\$ to +4 in [Mn{O_2}] . So, there is a decrease of 6 in oxidation number for 2 Manganese (Mn) atoms. Hence, 2 moles of \$KMn{O_4}\$ will be reduced by one mole of KI in an alkaline medium. Therefore, the correct answer is option (D).

How many moles of KMnO4 are reacted with one mole of ferrous oxalate in the acidic medium?

hence 3/5 moles of KMnO4 of KMnO4 will be needed to react completely with one mole of ferrous oxalate in acidic solution…..

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How many no of moles of KMnO4 are required to oxidise?

KMnO4 is at its maximum oxidation state and cannot be further oxidized. If you mean how many moles are needed to react with KMnO4 when it is used as on oxidizing agent, then it depends on the reaction. 8 moles of HCl are needed to react with 1 mole of KMnO4.

How many moles of KMnO4 are in an acidic medium?

In an acidic medium the sulphite ions get converted to sulphate ions. In the balanced chemical equation we can see that for 2 moles of potassium permanganate produces 5 moles or oxidises five moles of sulphite to sulphate ions. We can also say that 5 moles of sulfate reacts with 2 mole of potassium permanganate.

What is the volume of 0.1 m KMnO4?

The volume of 0.1M KMnO4 required to oxidise 20 ml of 0.1 M oxalic acid in acidic medium is 20 ml.

How many moles of MnO4 reduced to mn2+ by the addition of 7.5 moles of electrons to MnO4 -? *?

Answer: The number of moles is 24.

How many moles of KMnO4 reacted with oxalic acid?

0.4 moles of acidified KMnO4 is required to oxidize 1 mole of oxalic acid.

How many moles of KMnO4 are needed to oxidise a mixture of 1 mole of each feso4 & FeC2O4 in acidic medium?

Therefore, 2 moles of permanganate will be needed to oxidize one mole of \$Fe{{C}_{2}}{{O}_{4}}\$ , \$F{{e}_{2}}{{({{C}_{2}}{{O}_{4}})}_{3}}\$, \$FeS{{O}_{4}}\$ and \$F{{e}_{2}}{{(S{{O}_{4}})}_{3}}\$ in acidic medium.

How many moles of KMnO4 are required to oxidise 1 mole of feo0 93?

6 mol of MnO4−​ in acidic medium.

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How many moles of KMnO4 will Neutralise 1 mole of feso4 in acidic medium?

5 moles of reacts with 1 mole of in acidic medium.

How many moles of KMnO4 are required to oxidizes 5 moles?

Acidified KMnO4 reacts with SO32– ion as follows. 2 moles of KMnO4 produces= 5 (O).

What is the N factor of KMnO4?

n-factor is defined as the number of H + ions replaced by 1 mole of acid in a reaction. In neutral medium KMnO4 forms MnO2 (+7 to +4) i.e. it gains 3 electrons. So, n-factor= 3.

How many moles of ferrous oxalate are required?

Therefore we can say that \$0.6\$ moles are required to oxidise one mole of ferrous oxalate. Hence the correct answer is option (C).