**Contents**show

## What is the volume of 0.5 moles of n2 at STP?

0.5 moles⋅22.4 L/mol=11.2 L , and so on.

## What volume is occupied by 0.5 mole of nitrogen gas at STP?

As 1 MOLE of nitrogen gas occupied 22.4Litre by Avogadro equation,Then 0.5 moles of nitrogen gas occupied volume of 0.5*22.4=11.2Litre.

## What is the volume of n2 in STP?

Explanation: From this website, the new molar volume of a gas is 22.7 L .

## What is the volume of 7.08 moles of n2 at STP?

Explanation: At STP the molar volume of all gases is 22.4dm3/mol. So hence 7.08mol of any gas at STP would occupy a volume of 7.08×22.4=158.592dm3 .

## What is the mass of 0.5 mole of N2 gas?

mass of one mole of nitrogen gas is 28 gram(14*2) mass of 0.5 mole of nitrogen is 14 grams.

## What is the volume of 6.022 N2 of nitrogen at STP?

1 mole of any gas occupies 22.4 L of molar volume at NTP.

## What volume does .25 moles of oxygen gas occupy at STP?

Ernest Z. At STP (0 °C and 100 kPa), the volume of O₂ is 5.7 L. We can use the Ideal Gas Law to solve this problem.

## What is the volume of 1 mole of gas at STP?

What is the volume of 1 mole of an ideal gas at STP (Standard Temperature and Pressure = 0 °C, 1 atm)? So, the volume of an ideal gas is 22.41 L/mol at STP. This, 22.4 L, is probably the most remembered and least useful number in chemistry.

## What is the mass of 0.5 mole of H₂o?

=18 grams. Thus, the mass of 1 mole of water is 18 grams. Now, Mass of 1 mole of water =18 g. So, Mass of 0.5 mole of water =18×0.5g. =9g.

## What is the volume of 1.4 gram of N2 gas at STP?

d) the volume occupied by 1.4 g of N2 at STP is 1.12 dm3.

## What is the volume of 1 mole of nitrogen at STP?

At STP, 1 mole of gas is corresponds to 22.4 L of volume.

## What is the density of N2 at STP?

The density of nitrogen gas, N2 , at STP is 1.25 g/L .

## What volume will 0.750 moles of nitrogen gas N2 occupy?

At STP of 273.15 K and 1 atm , the volume of 0.750 mol N2 is 16.8 L N2 .

## What is the volume of nitrogen gas present in 7 moles of the gas at STP?

= 5.6 litres of volume.

## What volume would 10g of o2 occupy?

V=3.49≅3.5L.