# How many grams are in 0 75 moles of NaOH?

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The molar mass of NaOH is 40.0 g/mol, so there are 0.75mol⋅40.0g/mol=30g of NaOH, 30.

## How many grams are in a mole of NaOH?

The molar mass of the compound NaOH is 40 g/mol.

## What is the mass of 0.75 moles?

So, if there are 0.75⋅mol , the mass is 0.75⋅mol ×64.07⋅g⋅mol−1 ≅48⋅g .

## What is the mass of 0.75 moles of NaOH?

The molar mass of NaOH is 40.0 g/mol, so there are 0.75mol⋅40.0g/mol=30g of NaOH, 30.

## How many grams does NaOH have?

1 mole of sodium hydroxide has a mass of 40.00 g⋅mol−1 .

## How many moles are in NaOH?

First, the molar mass of NaOH is 39.997 g/mol. Divide the mass by the molar mass and you’ll have the equation: 60 g / 39.997 g/mol. The grams cancel and you are left with 1.50 moles of NaOH.

## How do you calculate moles of NaOH?

Step 1: Calculate the amount of sodium hydroxide in moles

1. Amount of solute in mol = concentration in mol/dm 3 × volume in dm 3
2. Amount of sodium hydroxide = 0.100 × 0.0250.
3. = 0.00250 mol.
4. The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H 2O(l)
5. So the mole ratio NaOH:HCl is 1:1.
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## How many moles are in 75 grams of sulfur?

Use the periodic table to check the atomic mass, this is the number of grams per mole → 1 mole of Aluminum is 26.982 g ▪ Written as a fraction this is … Step 3: Multiply step one by step two. Practice: How many moles are in 0.2 g of…

## How many particles are in 0.75 moles?

Explanation: Since we know that there are 6.022⋅1023 atoms in every mole of a substance (Avogadro’s Number), there are 6.022E23⋅0.750 atoms of Zn in 0.750 mols of Zn.

## How many moles are present in 80 grams of sodium hydroxide?

= 80 / 40= 2 mol .

## How many moles of NaOH are in 80.0 g of sodium hydroxide NaOH?

80 gm of NaOH is two moles so you have two moles of sodium thus two times Avogadro’s constant of sodium atoms. 80 gm of NaOH is two moles so you have two moles of sodium thus two times Avogadro’s constant of sodium atoms. Sodium hydroxide is an ionic compound.

## How many moles are in 4.75 g of sodium hydroxide?

4.75 g of NaOH (1.19 x 101 mol NaOH) Answer: The molar mass of NaOH was solve in section A to be 40 g/mol.